26-02-2017, 07:30 PM
It's easy enough to draw it for yourself.
You've already established that the base of the NPN transistor is fed from the 47k/10k potential divider between Vcc and earth.
The emitter is connected to earth by RE (1k) which has a bypass capacitor CE (no value stated).
The collector is connected to the 9V supply rail by RL (4k7) with the output being taken from the collector.
The input is to the base via C1 (no value).
That's all there is to it - you should be able to draw it in less time than it's taken me to type this!
You've already established that the base of the NPN transistor is fed from the 47k/10k potential divider between Vcc and earth.
The emitter is connected to earth by RE (1k) which has a bypass capacitor CE (no value stated).
The collector is connected to the 9V supply rail by RL (4k7) with the output being taken from the collector.
The input is to the base via C1 (no value).
That's all there is to it - you should be able to draw it in less time than it's taken me to type this!
