15-04-2012, 10:17 PM
I would have thought that the internal resistance of a freshly-charged accumulator would have been in the range of 0.1 to 0.2 ohm.
I consulted a few of my vintage wireless text-books on this matter and discovered the following. A good, freshly-charged lead-acid accumulator had an open-circuit voltage of 2.1 v. At a heavy discharge current of a few amps., that voltage would be expected to fall to 2.0v after about half-an-hour. At the more usual discharge of about 1 amp., (which is the design rating for this eliminator), the 2.0v figure would have been reached after about 3 hours.
Hence, in this design, setting the Vout pot. for 2.1v. off-load, falling instantaneously to 2.0v. on-load, would appear to be not harmful to the valves.
Al.
I consulted a few of my vintage wireless text-books on this matter and discovered the following. A good, freshly-charged lead-acid accumulator had an open-circuit voltage of 2.1 v. At a heavy discharge current of a few amps., that voltage would be expected to fall to 2.0v after about half-an-hour. At the more usual discharge of about 1 amp., (which is the design rating for this eliminator), the 2.0v figure would have been reached after about 3 hours.
Hence, in this design, setting the Vout pot. for 2.1v. off-load, falling instantaneously to 2.0v. on-load, would appear to be not harmful to the valves.
Al.
